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15x^2-93x+18=0
a = 15; b = -93; c = +18;
Δ = b2-4ac
Δ = -932-4·15·18
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7569}=87$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-93)-87}{2*15}=\frac{6}{30} =1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-93)+87}{2*15}=\frac{180}{30} =6 $
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